Does Anyone Know How to Change X-Drive Setting With Resistors?

Hi All. I've got a couple of the X-Drives, preset @ 290mA. I'm using them for a couple of 2 cell PL520 builds, and would like to get a little more current out of them.

Does anyone know which resistors are the set resistors and what the formula for calculating current with this switch is?

Thanks all.

I don't know anything about the X-drive, but this method will work with all constant current drivers you are unfamiliar with:

The sense resistor will be of low value and therefore easy to find. Usually <1Ω, but possibly a bit higher for lower current settings. First calculate the feedback voltage using ohm's law: you have current and resistance, you can get voltage. The driver will drive the output until it sees this voltage on the sense resistor, you see. So set up a new ohm's law equation with the known feedback voltage and plug in the current you want. Solve for the new resistance.

I believe these are the ones to be set.

Cyparagon, thank you again for your mathematical assistance. By 'feedback voltage', do you mean the combined Vf of the diode and the driver? When you say I have current, I assume you mean the current output of the driver. But, resistance? Am I just using the sense resistor for that variable in the equation?
I've found two lower resistance resistors:
R4 = 1R47
R5 = 2.0
I think I'm getting close...

The formula is .25/R=I

R4 = 1R47 --> 170mA
R5 = 2.0 --> 125mA

The total is 295mA.

ahh...so, .25 is the reference voltage? Thanks Blord. You're great. Now...I just doubt I can get a small amount more w/ the resistors I have on hand. I don't want to go above 315mA.

Rep for all if it lets me!

Edit: thanks again everyone...now, if I can just find a 1.8ohm resistor, I can get the 310mA I'm shooting for. If it proves to be more than just an exercise in CE analysis, I'll leave it alone.