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ArcticMyst Security by Avery

Invisible beam?

niiii

niiii

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I think diode is not dead because I tried 4x AA(1,5v) and the laser works but still weak but brighter than when I used single 18650. The 16340s 3V are bad I think because laser only flash when I use them.
 





niiii

niiii

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Today I measured the current of the driver... and with single 18650 it shows 100-160mA (laser works but very weak) and when I use 2x 16340 3V.. it only shows some numbers only for like a helf of a second and then 0.00A for the rest of time... when I disconnect the cable of the multimeter and connect again it shows still 0.00A but when I switch the laser Off and ON then its shows again those numbers and then 0.00A until restart... Then I measured the voltage of the driver without diode and its about 6V permanently...

EDIT: I tried 18650 + 1x 16340 together and I got 1,5A on the tailcap and the diode is still very weak...
 
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Garoq

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How did you measure the output? The driver needs to be attached to a dummy or test load to make accurate measurements.
 
NRGLite

NRGLite

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Diode might be defective. Try measuring the power of the batteries. That might be the problem.
 
niiii

niiii

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thats how I measured the current
IMG_1206.jpg
 
NRGLite

NRGLite

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Check the batteries. They may have a problem.
I remember once I built my 800 mW build, it was really weak and it couldn't light matches. However, once I charged the batteries, it lit up like crazy. So it may be the batteries.
Or you may have a defective module :scowl:.
 
niiii

niiii

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Im gonna get some diodes today for testload... how many should I use without resistor?

these diodes


Dummy_Load_1.jpg
 
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NRGLite

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I'm not sure it's a good idea to link up any without a resistor.
I'm not usre, could be wrong. ;)
 
Rifter

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Ill bet its your 3v 16340's that are the issue. Ill bet they just cant handle the current and are tripping the protection circuit in the batteries.

16340's arnt really a good battery type for 2amp+ draw situations.

Especially the 3v 16340's that are designed to replace CR123A's that are low draw batteries and cant support high current applications.
 
NRGLite

NRGLite

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Anyone correct me on the post? lotus dark_rose maybe? ;)
Rifter might be correct.
 
Rifter

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NRGLite said:
Anyone correct me on the post? lotus dark_rose maybe? ;)
Rifter might be correct.
Click to expand...

If you are measuring voltage then you will need a resistor, and then do the math to get amperage. If you are measuring amperage with a ammeter or a MM in ammeter mode then you do not need a resistor just hook it up in line with the output.
 
Lotus_Darkrose

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NRGLite said:
Anyone correct me on the post? lotus dark_rose maybe? ;)
Rifter might be correct.
Click to expand...

Lol, smart aleck. I'm sure I could muster up an "I'm not sure" answer as well ;)


Edit: Also, I just measured current at the tailcap on my A-140 laser. With 1x 18650 it is only drawing 250ma from the battery. It draws around 840ma from 2 18350 cells.
 
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