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Old 01-24-2009, 11:39 AM #1
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Default My proof that 2=1

Ok so start by letting X=1

Therefore
X[sup]2[/sup]=X

Subtract 1 from both sides
(X[sup]2[/sup]-1)=(X-1)

Difference of two squares
(X+1)(X-1)=(x-1)

Cancel out (X-1) and we have
(X+1)=1

Substitue 1 back in place of X and...
2=1

8-)

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Old 01-24-2009, 11:41 AM #2
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Default Re: My proof that 2=1

That is what happens when you.... :

Well I'll let you figure it out.



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Old 01-24-2009, 01:52 PM #3
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Default Re: My proof that 2=1

woah
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Old 01-24-2009, 05:10 PM #4
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Default Re: My proof that 2=1

And that's my proof that study = fail
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Old 01-24-2009, 05:40 PM #5
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Default Re: My proof that 2=1

Quote:
Originally Posted by Xplorer877
That is what happens when you.... :

Well I'll let you figure it out.



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Divide by zero?
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Old 01-24-2009, 07:15 PM #6
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Default Re: My proof that 2=1

Wrong,

[media]http://www.youtube.com/watch?v=II-_DanHx3I&amp;fmt=22[/media]

you can't cancel out (X-1) with (X-1) because you stated that X=1, ergo (1-1)=0 and you can't do 0/0.

Or this will happen:

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Old 01-24-2009, 08:28 PM #7
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Default Re: My proof that 2=1

That reminds me of this 1 I just saw recently.

Let a = x
a+a = a+x (add a to both sides)
2a = a+x (a+a=2a)
2a-2x = a+x-2x (subtract 2x from both sides)
2(a-x) = a+x-2x (2a-2x = 2(a=x))
2(a-x) = a-x (x-2x = -x)
2 = 1 (divide both sides by a-x)
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Old 01-24-2009, 09:41 PM #8
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Default Re: My proof that 2=1

Quote:
Originally Posted by nvme
That reminds me of this 1 I just saw recently.

Let a * = x * *
a+a * * = a+x * * (add a to both sides)
2a = a+x * * (a+a=2a)
2a-2x *= a+x-2x (subtract 2x from both sides) *
2(a-x) *= a+x-2x (2a-2x = 2(a=x))
2(a-x) *= a-x (x-2x = -x)
2 = 1 * * (divide both sides by a-x)

It's the same thing.
If a = x then (a-x) &lt;=&gt; (x-x) = 0, so you can't eliminate (a-x) with (a-x).
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Old 01-24-2009, 11:11 PM #9
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Default Re: My proof that 2=1

[s]Yup, just like you have to factor out binomials, you can't just &quot;divide to cancel&quot;, you actually have to divide them.

(a-x)/(a-x) is not equal to 1[/s]

Nevermind, I suck at math, it's as Niko said. *You basically set yourself for a fallacy by assuming a = x in the beginning, which would then mean:

a = x
a - x = x - x
a - x = 0

Therefore, (a-x) = 0, then (a-x)/(a-x) = 0/0 and you cannot divide by zero (see above pictures).
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Old 01-25-2009, 02:15 AM #10
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Default Re: My proof that 2=1

Yeah math fail. It will always either be a false answer or equal the original. The problem with algebra is that it always wins.

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Old 01-25-2009, 02:41 AM #11
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Default Re: My proof that 2=1

Quote:
Originally Posted by rocketparrotlet
Yeah math fail. *It will always either be a false answer or equal the original. *The problem with algebra is that it always wins.

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Old 01-25-2009, 06:44 AM #12
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Default Re: My proof that 2=1

LOL!



Yes dividing by zero can yield slightly odd results.
So this is my 744th post! ;D

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