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06022008, 07:18 PM  #1  
 
Banned Join Date: Mar 2008 Location: London, UK
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Me and a friend were bored in Physics and came up with this: a=1 b=1 a=b a[sup]2[/sup]=ab a[sup]2[/sup]ab=b[sup]2[/sup]ab therefore: a(ab)=b(ab) therefore: a=b 1=1 !!! someone please check our algebra but I think its right!!!  
06022008, 07:23 PM  #2  
 
Class 2 Laser Join Date: Oct 2007
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that acctuallylooks right lol
 
06022008, 07:25 PM  #3  
 
Banned Join Date: Mar 2008 Location: London, UK
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thats what concerns me I know that we arn't so good as to just proove 1=1 wheres the flaw though  
06022008, 07:45 PM  #4  
 
Cereal Eater 
the flaw is right there you cant simplify (ab) with (ab) just like that, you're eliminating results because you said that a=1 ^ b=1, therefore a=b. so ab = 0. if you operated: a*0 = b*0 > 0 = 0  
06022008, 07:54 PM  #5  
 
Banned Join Date: Mar 2008 Location: London, UK
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I cant see what the problem is i do it all the time in algebra but if you have found the prob kudos to you!  
06022008, 08:00 PM  #6  
 
Class 1M Laser Join Date: Mar 2008
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It's kind of like this one I found a while ago (actually in the phail thread here on LPF :P) study = no fail no study = fail no study + study = no fail + fail (no + 1) * study = (no + 1) * fail [s](no + 1)[/s] * study = [s](no + 1)[/s] * fail study = fail I also have one that shows women = evil, but I don't know if it will work in english *  
06022008, 08:07 PM  #7  
 
Banned Join Date: Mar 2008 Location: London, UK
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oh i didnt reaise this actually existed... it was just me and a friend messign around and then ZOMG we just disproved maths lol so I still dont understsand the prob?  
06022008, 08:07 PM  #8  
 
Class 3R Laser Join Date: Feb 2008
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06022008, 08:09 PM  #9  
 
Banned Join Date: Mar 2008 Location: London, UK
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someone explain?!
 
06022008, 08:15 PM  #10  
 
Cereal Eater 
its the same problem as 1=2, sorry but i have to leave home, i'll explain it to you later you just have to know that it is not possible, reread what i said before  
06022008, 08:16 PM  #11  
 
Banned Join Date: Mar 2008 Location: London, UK
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edit: never mind guys found it myself! we are dividing both sides of the equation by (ab) (ab)= 0 we are dividing by 0 which is mathematically impossible so it works technically in algebra but its wrong... sorry guys lol those of you with overdrafts are still indebted....  
06022008, 08:24 PM  #12  
 
Class 3R Laser Join Date: Feb 2008
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b=1(a=1b=1)=0 therefore: a=b, a=b, 0=0, no such thing as negative zero.  
06022008, 08:30 PM  #13  
 
Banned Join Date: Mar 2008 Location: London, UK
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b=1(a=1b=1)=0 therefore: a=b, a=b, 0=0, no such thing as negative zero. [/quote] no your algebra is wrong: 1(ab) = 1*0=1 not 0!  
06022008, 09:00 PM  #14  
 
Class 1 Laser Join Date: Sep 2007
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There is no particular problem with a negative zero; it has the same location on the real axis as a positive zero. However, in engineering computation generally, notably in the IEEE 754 floating point standard (that you computer adheres to :?), not only allowsbut actually demands tracking negative zero as well as positive zero. The convention is useful in some types of computations, so it is used. BTW, dividing anything finite by zero yields infinity, which, to paraphrase Woody Allen, stretches out a long way, especially toward the end.  
06022008, 09:18 PM  #15  
 
Class 3B Laser Join Date: Dec 2007
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The whole problem is division by 0.When you are simplifiyng with (ab) you are dividing by 0 because ab=0 because a=b.You know why division by 0 doesn't work :  
06022008, 11:00 PM  #16  
 
Class 3R Laser Join Date: Jan 2008 Location: BC, Canada
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edit: never mind guys found it myself! we are dividing both sides of the equation by (ab) (ab)= 0 we are dividing by 0 which is mathematically impossible so it works technically in algebra but its wrong... sorry guys lol those of you with overdrafts are still indebted....[/quote] Before reading all the way through this thread, I was going to post this link: http://en.wikipedia.org/wiki/Invalid...000171QINU.7F it's basically the same as your proof, and it points out the flaw where you're dividing by zero.... but I see you've realized that already
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