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Old 06-27-2009, 01:26 AM #1
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Default Using a pot to control a lasers power?

I was wondering if you used a 50k pot after the switch and before the driver would you be able to adjust to power from max to none on a laser would this work?

Also I would use this for a o-like <100mw, LOC and 8x so I think I would need less ohms so could anyone tell me how ohm's pot I will need?

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Old 06-27-2009, 01:35 AM #2
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Default Re: Using a pot to control a lasers power?

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Do you understand OHM's law? It is the law.

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Old 06-27-2009, 01:46 AM #3
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Default Re: Using a pot to control a lasers power?

No :/
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Old 06-27-2009, 02:58 AM #4
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Default Re: Using a pot to control a lasers power?

choose your max current with a DDL driver. Choose a resistor to use accordingly, to achieve your max current. For adjust ability, connect a 25ohm pot in series with your chosen resistor, this will give you a current range of about ~50mA to whatever your max current level is. Please tell me you know how to make a DDL driver.
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Old 06-27-2009, 02:59 AM #5
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Default Re: Using a pot to control a lasers power?

Quote:
Originally Posted by Hemlock_Mike View Post
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Old 06-27-2009, 03:31 AM #6
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Default Re: Using a pot to control a lasers power?

This would sorta work. Keep in mind though, it's really inefficient and backwards. Your drivers will always be set to their highest values, so make sure your drivers are capable of that current in a constant-on 100% duty cycle setting... Also keep in mind you're going to need one heck of a potentiometer... Whatever current you're resisting with your pot is being "thrown away" as heat. If you were to turn down a long open can at 420mA to its lowest setting your potentiometer would be dissipating 1.26 watts (!!!)
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Old 06-27-2009, 03:37 AM #7
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Default Re: Using a pot to control a lasers power?

I'm using a flexdrive and a o-like module so no ddl driver.

Btw I'm building this in a big suitcase so I getz teh heatsinking . (Fans ect)
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Old 06-27-2009, 03:48 AM #8
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Default Re: Using a pot to control a lasers power?

well the flexdrive is either always on, or always off. Once it's input voltage drops too low, it will simply shut off. It won't decrease its output ever.
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