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how laser energy loss over distance????
- Thread starter asdegypt
- Start date
Sigurthr
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Energy is only "lost" as it is absorbed by the matter it is passing through (air, usually). In a vacuum no energy would be lost, but the beam would still spread out.
upaa27
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Depends on the focus of it. You can determine the power by doing:
Order of magnitude of the beam's solid angle is approximately wavelength/area of the laser's output aperture is approximately (the vertex angle of divergence)^2
This will tell you it's spread and therefore you can calculate the beam's focal point and therefore at what distances you are receiving full power in a vacuum
An example is:
wl: 500nm
Area of aperture: 5mm^2
So:
Order of magnitude of the beams solid angle (estimate sign) (500)^2*10^-18 m^2/5^2*10^-6)=10^-8 so the vertex angle of divergence is 1/10 milliradians
That is just for checking the power without the lens or an lpm
Hope this helps
PLEASE correct me guys if this is the wrong formula.
Order of magnitude of the beam's solid angle is approximately wavelength/area of the laser's output aperture is approximately (the vertex angle of divergence)^2
This will tell you it's spread and therefore you can calculate the beam's focal point and therefore at what distances you are receiving full power in a vacuum
An example is:
wl: 500nm
Area of aperture: 5mm^2
So:
Order of magnitude of the beams solid angle (estimate sign) (500)^2*10^-18 m^2/5^2*10^-6)=10^-8 so the vertex angle of divergence is 1/10 milliradians
That is just for checking the power without the lens or an lpm
Hope this helps
PLEASE correct me guys if this is the wrong formula.
Last edited:
