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Old 02-08-2010, 11:17 PM #1
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Default V5 Flexdrive cutoff voltage

The cut off voltage for a v5 flexdrive is 2 volts, right? If I add a diode in series with the driver, then technically the cut off voltage will be 2.7 volts, right?

Reason I ask is because I'm using a CR2 host, and CR2's are not protected. If I make the cut off voltage 2.7 volts instead of 2 volts, then I shouldn't have to worry about over discharge, correct? Thanks.


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Old 02-08-2010, 11:19 PM #2
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Default Re: V5 Flexdrive cutoff voltage

The diode doesn't change the driver, just what is coming into the driver.

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Old 02-08-2010, 11:22 PM #3
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Default Re: V5 Flexdrive cutoff voltage

I should have been more clear :P

If a battery sags down to 2.7 volts, and I have a diode between the battery and that driver, then the driver will cut off right?
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Old 02-09-2010, 12:47 AM #4
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Default Re: V5 Flexdrive cutoff voltage

mfo ---
You may need to direct this question directly to DrLava but IIRC, the V5 has a reverse polarity protection built in which may give you that extra 0.7 volt edge. If the circuit uses Shottke diodes, then some battery protection may be provided.

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Old 02-09-2010, 12:52 AM #5
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Default Re: V5 Flexdrive cutoff voltage

Thanks Mike, I will shoot him a PM.
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Old 02-09-2010, 07:23 PM #6
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Default Re: V5 Flexdrive cutoff voltage

Hi mfo, the reverse polarity protection on the FlexDrive is highly efficient - it presents almost no additional voltage drop to the driver. If you are using an unprotected cell, yes your series diode solution should perform as expected.
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Old 02-09-2010, 08:53 PM #7
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Default Re: V5 Flexdrive cutoff voltage

Quote:
Originally Posted by drlava View Post
Hi mfo, the reverse polarity protection on the FlexDrive is highly efficient - it presents almost no additional voltage drop to the driver. If you are using an unprotected cell, yes your series diode solution should perform as expected.
Thanks Dr. Lava! +1
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