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SF-AW210 PIV plots/lifetime thread

daguin

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I like your thinking about a 'long life' 8X build though...
I have mine set at a fairly conservative 292mA's, mine is a slightly lower efficiency BDR diode and is under 400mW's at that current. But it is still a ton of power at 375mW's!
So much, that I would think even 300mW's would be plenty for a long lasting 8X build. :)

This is OT, but while we wait . . . .

I have built two more 8X's in Kryton Grooves. I am waiting for IgorT's test results for the final setting and subsequent sale. I set both of them at 310mA. With the 405-G-1 lens one puts out 415mW The other puts out 490mW!!!

Go figure, eh?

Guess I should put this in the 8X diodes thread, huh

Peace,
dave
 
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jayrob

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490mW's at only 310mA's!!!

Man, that's a HOT diode! Good for you Dave! ... (I'm jealous)
 
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Hey guys just wanted to say that this graph helps alot and I just want to make sure I'm reading the graph correctly...190ma at ~4.75 Volts is going to give me ~200mw.
 
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Hansolo777;

That current will give you over 200mw.

Diode voltage will change with the actual temperature of the diode.

LarryDFW
 

nospin

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with my 210 after a lot of research decided on 189ma
that gives 250mw+ with a Jayrob lens
 
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So, 250mA is generally, probably, safe for an SF-AW210, and I *might* even get up to 300mW out of it. Am I correctly reading your graph, or did I miss something?
 

nospin

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I wanted mine to last around 100 hours
others have posted an early death at over 200ma drive current
I'm getting 255mw @ 189ma with the Jayrob lens
You get what you pay for and to try to overdrive the diode to get
more than that is just foolish!
My next 405nm will be a 12x then I can get 550mw just as conservatively
 
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If I was to use two lithium cells, each rated at 3.6V, with a rckstr driver, I wouldn't be able to run this at an *especially* high current due to the Vf of the diode increasing with the current, and the drop through the driver? Maybe 150mA or so, according to your graphs? But if I used 3.7V cells, I could get up to about 170-180mA?
 
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If I was to use two lithium cells, each rated at 3.6V, with a rckstr driver, I wouldn't be able to run this at an *especially* high current due to the Vf of the diode increasing with the current, and the drop through the driver? Maybe 150mA or so, according to your graphs? But if I used 3.7V cells, I could get up to about 170-180mA?

Rckstr drivers need at least 2 volts above the output voltage. If you set your diode to run at 200mA the diode will need about 5.3 volts. Your battery should supply 7.3v, you'll be cutting it close with 2 3.7v cells.

-Tony
 
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Rckstr drivers need at least 2 volts above the output voltage. If you set your diode to run at 200mA the diode will need about 5.3 volts. Your battery should supply 7.3v, you'll be cutting it close with 2 3.7v cells.

-Tony

It's listed as needing 2.25V, and I'm thinking an SF-AW210 at 170mA, which was about 5.15V or so.
 
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It's listed as needing 2.25V, and I'm thinking an SF-AW210 at 170mA, which was about 5.15V or so.

Either way you'll still be cutting it close as you're batteries drain. Voltage regulation can only be guaranteed with the appropriate input voltage. I'm actually in the same boat you are. I have a 6x on the way and I already have a few extra Rkcstr drivers. But I think I'm gonna have to buy a flexdrive and only use one 3.7v CR123a cell. Rkcstr Drivers are best for 650nm diodes because they only take about 3-4 volts.

-Tony
 
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If I was to use two lithium cells, each rated at 3.6V, with a rckstr driver, I wouldn't be able to run this at an *especially* high current due to the Vf of the diode increasing with the current, and the drop through the driver? Maybe 150mA or so, according to your graphs? But if I used 3.7V cells, I could get up to about 170-180mA?

The charged voltage of 2 lithium ion batteries is 8.4 VDC.

So you can operated down to 7.3 VDC or so.

LarryDFW
 
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Yes, but they're only above the nominal voltage for a short period of time, especially when under a considerable load.
 




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